Yoshinobu Yamamoto allowed one run on five hits and one walk during a six-inning gem Friday as the Los Angeles Dodgers defeated the Toronto Blue Jays 3-1 to force Game 7 in the World Series.
Los Angeles scored all three of its runs in the third inning off Toronto starter Kevin Gausman, with Mookie Betts delivering a key two-run single.
The Blue Jays made things interesting in the ninth, trailing by two. After Dodgers right-hander Roki Sasaki hit Alejandro Kirk with a pitch to begin his second inning of work, Addison Barger crushed a ball to the left-center field gap that looked like it would score pinch runner Myles Straw from first.
Barger’s ball got wedged in the bottom of the wall, however, meaning Straw had to stop at third and Barger at second.
Game 3 starter Tyler Glasnow replaced Sasaki and recorded the final three outs in relief for the Dodgers with an assist from Kiké Hernández, who made a heads-up double play to end Game 6.
“Somehow I was able to hear that the bat broke, even with that crowd,” Hernández told Ken Rosenthal of Fox Sports. “The crazy thing is I had no idea where the ball was cause it was in the lights the whole time.”
It was the first game-ending 7-4 double play in postseason history, according to MLB.com’s Sarah Langs.
“I was being too aggressive,” Barger said of his baserunning mistake after the game. “It was kind of a bad read.”
Gausman was terrific in a losing effort for the Blue Jays, striking out eight over six frames. Toronto’s lone run came off the bat of George Springer, who returned to the lineup and went 2-for-4.
Game 7 takes place Saturday in Toronto with the Blue Jays attempting to win their first World Series since 1993 against the defending champions.
“It’s Game 7 of the World Series at your home stadium,” Blue Jays manager John Schneider told reporters after the loss. “What the hell else could you want?”
Max Scherzer will start for the Blue Jays. The Dodgers haven’t announced their starter yet.
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